**Guide :High School **

# what is the vertex for the equation f(x)=3(x+4)^2-5

What is the vertex for the equation f(x)=3(x+4)^2-5**Take derivative..f'(x) = 3*2*(x+4)f'(x) is must be equal to 0.6*(x+4)=0x=-4for x=-4; what is the y value?for x=-4; f(x)=-5the vertex is (-4,-5)**...