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The Lees have 3 children. The oldest is twice as old as the youngest. The middle is 5 years older than the youngest. If the sum of the age is 57, how old

The Lees have 3 children. The oldest is twice as old as the youngest. The middle is 5 years older than the youngest. If the sum of the age is 57, how old is each child?
Oldest = 2 times Youngest -> O = 2*YMiddle = Youngest + 5 -> M = Y+5All of them together is 57 -> O + M + Y = 57So you have these three equations:(1) O = 2*Y(2) M = Y+5(3) O + M + Y = 57Now you want to reduce the number of variables. You can change the second equation to be Y = M-5 and then plug in "M-5" wherever there is currently a Y:(4) O = 2*(M-5) = 2*M - 10(5) O + M + (M-5) = 57     which becomes O + 2M = 62Then you plug in the "O" equation (4) into (5) which gives you(2M-10) + 2M = 62 which reduces to 4M = 72.So now I know M is 18. I can now plug that into my other equations:(4) O = 2*18 - 10 which means O = 26.Now I plug that into (1) from the top:26 = 2*Y which becomes 13 = YSo now I have O, Y, and MOldest is 26Middle is 18Youngest is 13Reading the sentence again, you can see that this makes sense.  ...

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